[最も共有された! √] simplify (x^3-y^3)^3 (y^3-z^3)^3 (z^3-x^3)^3/(x-y)^3 (y-z)^3 (z-x)^3 166282

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SOLUTION 1 Begin with x 3 y 3 = 4 Differentiate both sides of the equation, getting D ( x 3 y 3) = D ( 4 ) , D ( x 3) D ( y 3) = D ( 4 ) , (Remember to use the chain rule on D ( y 3) ) 3x 2 3y 2 y' = 0 , so that (Now solve for y' ) 3y 2 y' = 3x 2, and Click HERE to return to the list of problems SOLUTION 2 Begin with (xy) 2 = x y 1 Differentiate both sidesValue (x y)3 (y z)3 (z x)3 is (1) (x y)3 (y z)3 (z x)3 (2) 3 (x y) y3 z3 3xyz (4) x3 y3 z3 2x2y 2y2z 2z2x

Simplify (x^3-y^3)^3 (y^3-z^3)^3 (z^3-x^3)^3/(x-y)^3 (y-z)^3 (z-x)^3

Simplify (x^3-y^3)^3 (y^3-z^3)^3 (z^3-x^3)^3/(x-y)^3 (y-z)^3 (z-x)^3-Use sum of cubes identity to find x^3y^3z^3 = (xyz)(x^2y^2xyzz^2) Use the sum of cubes identity a^3b^3=(ab)(a^2abb^2) with a=xy and b=z as follows x^3y^3z^3 =(xy)^3z^3 =((xy)z)((xy)^2(xy)zz^2) =(xyz)(x^2y^2xyzz^2)Consider x 3 y 3 − z 3 3 x y z as a polynomial over variable x Find one factor of the form x^ {k}m, where x^ {k} divides the monomial with the highest Explanation You can simplify this expression by using (x 3)1 3 as a commonfactor Focusing solely on the exponents, you need to find the relationship between 1 3, the exponent of the first term, and 4 3, the exponent of the second term, so that 1 3 x = 4 3 ⇒ x = 4 3 − 1 3 = 3 3 = 1 If you use (x 3)1 3 as a common factor, you can

X2 Y2 3 Y2 Z2 3 Z2 X2 3 2 23 2 23 53 3 X Y Scholr

X2 Y2 3 Y2 Z2 3 Z2 X2 3 2 23 2 23 53 3 X Y Scholr

Your answer would be x^4yz/3 so simplified it would be 3x^4y^4z^2/6y^3z^3 Now simplify the z's bring z^3 to the numerator And get 3 x^4 y^4 z^2 (z^3) /6y^3 z^2 (z^3) is z because when multiplying your exponents add or subtract depending on whether a number is negative or positive In this problem its like (23)= 1 and z^1 is zU xx= 6x 6 u y= 6xy 6y;Find the value of X, Y and Z calculator to solve the 3 unknown variables X, Y and Z in a set of 3 equations Each equation has containing the unknown variables X, Y and Z This 3 equations 3 unknown variables solver computes the output value of the variables X and Y with respect to the input values of X, Y and Z coefficients Simplify ((x^2 y^3 z^(2) )^(3) (x^(3) yz^3 Simplify ((x^2 y^3 z^(2) )^(3) (x^(3) yz^3 )^(1/2))/(xyz^(3) )^(5/2) Latest Problem Solving in Fundamentals in Algebra More Questions in Fundamentals in Algebra Online Questions and Answers in Fundamentals in Algebra Series

WINDOWPANE is the livestreaming social network, and multimedia app, for recording and sharing your amazing life Post comments, photos and v simplify (x^3 y^3)^3 (y^3 z^3)^3 (z^3 x^3)^3/(x y)^3 (y z)^3 (z x)^3X^z = exp(z ln(x)) when x is a positive real and z is complex This is the only operation x^y on the domain x positive real, y complex which satisfies all of (1)(7) Because of this and other reasons, it is accepted as the modern definition of exponentiation From the identities sin x = x x^3/3!

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